Saturday, September 24, 2016

Install Android 7.0 Nougat in PC Hard-Drive | Dual-Boot with Windows OS

1. Download Android Nougat 7.0 ISO file[Developed by Android x86].
2. Download Rufus win App to Create Bootable/Live USB.
3. Insert USB with Minimum 4GB and select Downloaded ISO file and finally start.
4. After Finishing, Create New/ Separate Partition in PC for Android to be Installed with Minimum of 16GB Disk Size and Format it as FAT32.
5. After formatting, Reboot PC.
6. Boot PC from USB.
7. Select Install android x86 to HDD.
8. Now In bluescreen Select the Separate Fat32 formatted Partition to Install.
9. Do not Format.( I didn't formatted and it works fine).
10. Install Boot Loader GRUB.( It will replaces default Windows Bootloader).
12. Next it shows up that your are having Windows Partition and asked to create boot item for windows. Select Yes for that else you won't be able to boot into Windows next time.
13. Next Select Skip for EFI GRUB2.(I Skipped and worked for me, I think because I'm having Legacy PC).
14. Then Select Yes to Create Read/Write enabled system directory.
15. Now To create data.img, select yes and then Enter the Size you need for System Memory in MBs (1GB-1024MB).
16. Now Accept Reboot and then Boot Android from GRUB Menu.
17. Thats all . You have Successfully installed Android 7.0 nougat in your PC HDD.
Also I Made an Video Tutorial in YouTube for Better Understanding. You can Checkout if you don't understand or if any error pops.
https://www.youtube.com/watch?v=o90a...M(TechGeekShan).

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